(1/x+2)^2-5(1/x+2)-24=0

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Solution for (1/x+2)^2-5(1/x+2)-24=0 equation: 



(1/x+2)^2-5(1/x+2)-24=0



Domain of the equation: x+2)^2!=0

x∈R





Domain of the equation: x+2)!=0

x∈R



We multiply parentheses

(1/x+2)^2-5x-10-24=0

We multiply all the terms by the denominator


(1-5x*x+2)^2-10*x+2)^2-24*x+2)^2=0

We add all the numbers together, and all the variables

(-5x*x+3)^2-10*x+2)^2-24*x+2)^2=0

We add all the numbers together, and all the variables

-10x+(-5x*x+3)^2+2)^2-24*x+2)^2=0

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